分别分解。如有：
DIM x() AS STRING,y() as string,s as string
DIM i as integer,j as integer
s="a1,a2,a3;b1,b2,b3,b4"
x=split(s,";") ' 结果x有两个元素："a1,a2,a3"和"b1,b2,b3,b4"
for i=LBOUND(X) TO UBOUND(X)
y=split(x(i),",")
for j=LBOUND(y) to UBOUND(y)
print y(j),
next j
print
next i
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