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一个分数的分子分母之和为21,分母增加19后可约成1⼀4,则原分数为多少?

2025-04-08 08:07:26

推荐回答（2个）

回答1：

一个分数的分子分母之和为21,分母增加19后,分子分母之和是21+19=40
其中分母是分子的4倍
设分子为一倍数,则分母为4倍数,即
分子=40÷(1+4)=8
分母=8×4=32
原分数为
8/(32-19)=8/13

回答2：

分母增加19可约为1/4,则此时分子分母和为21+19,分子占一份,分母占四份,即和为五份,所以分子为:(21+19)/(1+4)=8,分母为:8x4-19=13,即原分数是8/13

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