已知cosα=1⼀3,且-∏⼀2<α<0,求[cos(-α-∏)sin(2∏+α)]⼀[cos(-α)cos(∏+α)]

求解!要过程!
2024-12-03 03:54:15
推荐回答(1个)
回答1:

原式=

  cos(α+π)sin(α)
=------------------------
  cos(α)[-cos(α)]

  sin(α)
=------------ (∵-π/2<α<0∴cos(α)>0且sin(α)<0 , ∴原式符号为负)
  cos(α)

  1-cos²(α)
=---------------
  cos(α)

  1-1/9
=-(--------)
  1/3
=-8/3