解一元一次方程,去括号的依据是什么?

2024-11-27 15:29:12
推荐回答(4个)
回答1:

1.括号前面有"+"号,把括号和它前面的"+"号去掉,括号里各项的符号不改变
2.括号前面是"-"号,把括号和它前面的"-"号去掉,括号里各项的符号都要改变
去括号法则的依据实际是乘法分配率
注: 要注意括号前面的符号,它是去括号后括号内各项是否变号的依据.
去括号时应将括号前的符号连同括号一起去掉.
要注意,括号前面是"-"时,去掉括号后,括号内的各项均要改变符号,不能只改变括号内第一项或前几项的符号,而忘记改变其余的符号.
若括号前是数字因数时,应利用乘法分配律先将数与括号内的各项分别相乘再去括号,以免发生错误.
遇到多层括号一般由里到外,逐层去括号,也可由外到里.数"-"的个数.
[编辑本段]例题
例1:先去括号,再合并同类项
(1) 5a-(2a-4b) ;
(2) 2x2+3(2x-x2)
解:(1)5a-(2a-4b)
=5a-2a+4b
=3a+4b
(2)2x2+3(2x-x2)
=2x2+6x-3x2
=-x2+6x

回答2:

依据是,乘法分配律

回答3:

解出来好解嘛 前有- 就和里面的数相乘 也就是负负的正 +就直抄

回答4:

应该是去括号法则和合并同类项法则吧。。我们老师告诉我们的啊、

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