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以0.1mol⼀l的naoh溶液滴定20ml同浓度的

2025-04-01 18:30:31

推荐回答（1个）

回答1：

NaOH与盐酸一比一反应,此题浓度又相同,滴加18 ml 0.1mol/L的NaOH,此时剩余盐酸,相当于2ml ,物质的量0.002LX0.1mol/L,再除以总体积20+18ml 也就是0.038L,则氢离子浓度为0.002乘以0.1,再除以0.038,最后再取负对数

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