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石墨做电极，电解AgNO3溶液，求电极反应式以及原理！！

2025-03-25 12:24:44

推荐回答（2个）

回答1：

银离子的氧化性强于水中氢离子，所以阴极银离子放电，得电子。
阴极：（Ag+）+（e-)=Ag↓
水中氢氧根的还原性强于硝酸根，所以阳极氢氧根放电，失电子。
阳极：2(OH-)-4(e-)=O2↑+2H+
总反应：4(Ag+)+2(OH-)==(点解）==4Ag↓+O2↑+2(H+)

回答2：

阴极反应：4Ag+
4e-
==4Ag(沉淀)
阳极反应：4OH-
+4e-
==2H2O+O2(气体)
总反应:4AgNO3
+
2H2O
==
4HNO3
+
4Ag(沉淀)
+
O2(气体)
阴极生成单质银，阳极生成氧气。因为银离子比氢离子得电子能力强，氢氧根离子比硝酸根离子失电子能力强。
希望可以帮到你

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