弹簧弹性系数K如何用公式计算

2025-03-15 06:24:42
推荐回答(4个)
回答1:

设弹簧平衡点为原点,x为弹簧末端位移,w为弹簧频率,可用2*3.14/T(T为周期)求,则有公式x=A*cos(w*t+a),现在对其求导,
wt+a的导数是w,cos(x)的导数是-sin(x),所以v=-w*A*sin(w*t+a),继续求导,sinx`=cosx,
结果a=-w^2cos(wt+a),根据公式F=ma=kx,k=-w^2*m

回答2:

用受到力与弹簧的伸长量的比值来计算。k=F/X.
也用同样的方法解决,自己琢磨吧。
我现在只能这么回答。没有太明白你的意思,问别人把。

回答3:

读图分析可知,底端弹簧所受拉力为g,顶端弹簧所受拉力为3g,则△l1=
3g
k1
,△l2=
g
k2
,又因为k1=3k2,所以△l1:△l2=
3g
k1

g
k2
=1:1.
故选a.

回答4:

k=f/L
f弹力,L为弹簧长度的变化量,都可以通过测力计和直尺测量。

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