1、原式=(x+1)^2-(2x-3)^2
=(x+1+2x-3)(x+1-2x+3)
= -(3x-2)(x-4)
2、原式=(25a^2-20ab+4b^2)
=(5a-2b)^2
自己检查一下啊,我总马虎
(x+1)^2-(2x-3)^2
=[(x+1)+(2x-3)][(x+1)-(2x-3)]
=(3x-2)(-x+4)
=-(3x+2)(x-4)
25a^2- 20ab+ 4b^2
=(5a)^2-2*(5a)*(2b)+(2b)^2
=(5a-2b)^2
a^2-b^2=(a+b)(a-b)
(x+1)^2- (2x-3)^2 =(3x-2)(-x+4)
aa-2ab+bb=(a-b)^2
25a^2- 20ab+ 4b^2=(5a-2b)^2
(x+1)^2- (2x-3)^2
=(x+1+2x-3)(x+1-2x+3)=(3x-2)(4-x)
25a^2- 20ab+ 4b^2
=(5a-2b)^2
1.=(x+1-2x+3)(x+1+2x-3)
=(4-x)(3x-2)
2.=(5a)^2-2*5*2ab+(2b)^2
=(5a-2b)^2