一个圆柱形水池底面直径为20米,深2米。这个水池的占地面积是多少?要挖这个水池,需要挖土多少立方米?

2025-03-31 15:01:40
推荐回答(4个)
回答1:

占地面积:
3.14×(20÷2)²
=3.14×100
=314平方米

需要挖土:
314×2=628立方米

侧面积=3.14×20×2=62.8×2=125.6平方米

铺瓷砖面积:
314+125.6=439.6平方米

需要栏杆:
3.14×20=62.8米

【润无声】为你解答。祝你学习进步!
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回答2:

这个水池的占地面积是3.14×(20/2)²=314平方米
铺瓷砖的面积是314+3.14×20×2=439.6平方米
栏杆3.14×20=62.8米

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回答3:

是一道求面积求体积的题目。

1、占地面积及圆面: πR2=100π平方米
2、挖土及体积:底面积X高=100π*2=200π立方米
3、底面和四周铺上瓷砖及求表面积=2πr*2+πR2=80+100=180平方米
4、栏杆及周长=2πr=20π米

回答4:

先求半径r=20乘1/2=10米。S=π·r的平方=3.14乘10乘10=314平方米。用底面积乘高=314乘2=618立方米。

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