硫酸亚锡(SnSO4)是一种重要的硫酸盐,广泛应用于镀锡工业.某研究小组设计SnSO4制备路线如下:查阅资料

2025-03-16 17:09:16
推荐回答(2个)
回答1:

(1)锡元素与碳元素属于同一主族,处于ⅣA族,原子核电荷数为50,则:50-2-8-8-18=14,故Sn处于第五周期,则在周期表中的位置为:第五周期第ⅣA族,
故答案为:第五周期第ⅣA族;
(2)由流程图可知,操作Ⅰ是从溶液中得到含结晶水的晶体,只能采取蒸发浓缩、冷却结晶、过滤、洗涤得到,
故答案为:蒸发浓缩、冷却结晶、过滤、洗涤;
(3)由信息可知,SnCl2易水解生成碱式氯化亚锡,存在平衡Sn Cl2+H2O?Sn(OH)Cl+HCl,加入盐酸,使该平衡向左移动,抑制Sn2+水解,
故答案为:SnCl2水解,发生SnCl2+H2O?Sn(OH)Cl+HCl,加入盐酸,使该平衡向左移动,抑制Sn2+水解;
(4)由信息可知,Sn2+易被氧化,加入Sn粉除调节溶液pH外,还防止Sn2+被氧化;  
故答案为:防止Sn2+被氧化;
(5)反应Ⅰ得到沉淀是SnO,Sn元素化合价为变化,属于非氧化还原反应,同时生成气体,该气体为二氧化碳,离子方程式为:Sn2++CO32-═SnO↓+CO2↑,
故答案为:Sn2++CO32-═SnO↓+CO2↑;
(6)酸性条件下,SnSO4还可以用作双氧水去除剂,双氧水有强氧化性,将Sn2+易被氧化为Sn4+,自身被还原为水,离子方程式为:Sn2++H2O2+2H+═Sn4++2H2O,
故答案为:Sn2++H2O2+2H+═Sn4++2H2O;
(7)令锡粉中锡的质量分数为x,则:
     Sn~Sn2+~2Fe3+~2Fe2+
1
3
K2Cr2O7计算.
   119g                     
1
3
mol       
  1.226g×x            0.100mol/L×0.032L
119g
1.226x g
=
1
3
mol
0.100mol/L×0.032L

解得x=93.2%,
故答案为:93.2%.

回答2:

19%硫酸亚锡溶液,125g/L的二价锡,17-19.5%的硫酸亚锡溶液配制的时候,硫酸亚锡和硫酸的比例很难掌握,配制时候很容易沉淀,中&镀&科技好像有19%硫酸亚锡溶液

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