(1)∵在△ABC中,b2=a2+c2? 3 ac.∴cosB= a2+c2?b2 2ac = 3 2 ∵B∈(0,π),∴B= π 6 …(3分)∵c= 3 b,∴根据正弦定理,得sinC= 3 sinB= 3 sin π 6 = 3 2 ∵C∈(0,π),∴C= π 3 或C= 2π 3 …(6分)当C=