打印一张九九乘法表的 C语言程序怎样编写？

#include
#include
main()
{
int i,j,s;
for(i=1;i<=9;i++)
{
for(j=1;j<=i;j++)
{
s=j*i;
printf("%d * %d=%3d",j,i,s);
}
printf("\n");
}
system("pause");
}
我用的是Dev c++做的，所以最后一句有system("pause"); 望参考

|1X1= 1
|1X2= 2|2X2= 4
|1X3= 3|2X3= 6|3X3= 9
|1X4= 4|2X4= 8|3X4=12|4X4=16
|1X5= 5|2X5=10|3X5=15|4X5=20|5X5=25
|1X6= 6|2X6=12|3X6=18|4X6=24|5X6=30|6X6=36
|1X7= 7|2X7=14|3X7=21|4X7=28|5X7=35|6X7=42|7X7=49
|1X8= 8|2X8=16|3X8=24|4X8=32|5X8=40|6X8=48|7X8=56|8X8=64
|1X9= 9|2X9=18|3X9=27|4X9=36|5X9=45|6X9=54|7X9=63|8X9=72|9X9=81
Press any key to continue

#include
main()
{
for (int i=1;i<=9;i++)
{
for (int j=1;j<=i;j++)
printf("|%dX%d=%2d" ,j,i,i*j);
printf("\n");
}
}

#include
main()
{
for (int i=1;i<=9;i++)
{
for (int j=1;j<=i;j++)
printf("%dX%d=%2d " ,j,i,i*j);
printf("\n");
}
} }
}