1+1/(x-1)+1+1/(x-4)=1+1/(x-2)+1+1/(x-3)1/(x-1)+1/(x-4)=1/(x-2)+1/(x-3)(2x-5)/(x-1)(x-4)=(2x-5)/(x-2)(x-3)因此2x-5=0, 得：x=5/2或(x-1)(x-4)=(x-2)(x-3)=0, 得：x^2-5x+4=x^2-5x+6, 不符。故只有一解为x=5/2
