函数y=x-1⼀2x(x∈[1,2]的值域

2025-03-22 12:29:16
推荐回答(1个)
回答1:

y=f(x)=x-1/(2x)
2>=x1>x2>=1
f(x1)-f(x2)=(x1-x2)-(1/2x1-1/2x2)
=(x1-x2)(1+1/(2x1x2))>0递增
1-1/2<=y<=2-1/4
1/2<=y<=7/4