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阿Q吧 > 求助，定积分求极限题。怎么做？在线等。。

求助，定积分求极限题。怎么做？在线等。。

2025-03-15 02:28:29

推荐回答（3个）

回答1：

原式>=0 是显然的

注意到 x <= 1/2

所以原式<= lim ∫ (1/2)^n/(1+x) dx = lim (1/2)^n ln(3/2) =0

所以原式=0

回答2：

0<被积函数<(1/2）^n，故0<积分值<(1/2）^(n+1)，夹逼定理有极限为0

回答3：

我是幼儿园毕业的，高难度的问题，我不懂

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