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阿Q吧 > 洛必达法则求极限 lim[e^x-e^(-x)]⼀sinx x→0 limsin3x⼀sin5x x→0 limxcot2x x→0

洛必达法则求极限 lim[e^x-e^(-x)]⼀sinx x→0 limsin3x⼀sin5x x→0 limxcot2x x→0

2025-04-03 23:20:08

推荐回答（1个）

回答1：

解：先判断条件：都是符合的 0/0型
1 原式=lim[e^x+e^x]/cosx 再判断条件不符合了，于是原式=2
2.原式=lim3cos3x/5cos5x 再判断条件不符合了，于是原式=3/5
3.原式=limx/tan2x=lim(1+4x^2)/2 再判断条件不符合了，于是原式=1/2

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