有一圆弧板,以知圆的直径为D=1520MM,弧的高度为H=70MM,请问弧长C是多少?弧半径为R,弧所对的圆心角为A。R=D/2=1520/2=760MMA=2*ARC COS((R-H)/R) =2*ARC COS((760-70)/760) =49.57度 =49.57*PI/180 =0.865124弧度C=R*A=760*0.865124=657.5MM
L=1520/2-70圆心角a=2*arccos(L/R)弧长=a*R