设x=根号3-2分之1,y=根号3+2分之1,求代数式x+y分之x的平方+xy+y的平方的值

2024-12-04 06:32:16
推荐回答(2个)
回答1:

∵ X= √ 3 -1/2 Y=√ 3+1/2
∴ X + Y= 2√ 3   XY = 3-1/4 = 11/4
又 ∵ (X² +XY+Y² )/(X+Y)
    =[(X+Y²)-XY] /(X+Y)
=(X+Y)-XY/(X+Y)
    =2√ 3-( 11/4 )/2√ 3
    =37√ 3/24

回答2:

看不懂你那个x+y分之x,你说的是x+y为分母还是y为分母