四年级二班第一小组种树,如果每人种5棵,还剩14棵。如果每人种7棵,就缺4棵。问这个小组有几人?

不用解方程,求详细过程
2025-04-07 07:34:56
推荐回答(4个)
回答1:

每人种5棵,还多14棵;
每人种7棵,还少4棵
也就是说,每人多种2棵, 就一共多种了14+4=18棵,所以,一共有18÷2=9(个),就是9个人。
即,一共9个人。
每人种5棵,一共9个人,这样种还有14棵,那么5×9+14=59(棵)
即,共59棵树。
以上就是分析,希望你可以理解。

回答2:

如果每人种5棵,还剩14棵。如果每人种7棵,就缺4棵。

很明显,在每个人都种5棵的基础上,如果每个人多种两棵,说明可以多种18棵。那么不用方程应该都能算了吧?9个人。

回答3:

5x+14=7x-4
x=9
或者题目可以描述为5的倍数与14的和等于7的倍数减4的差。推下来的重合的数就是59,则小组有9个人。

回答4:

设第一小组共种X棵树
(X-14)/5=(X+4)/7
得到X=59
有四年级二班第一小组共有9个人

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