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玄长3.6米，拱高0.3米！求弧长多少？

2025-04-01 06:28:16

推荐回答（3个）

回答1：

如下图所示，设所求圆弧半径为x.根据勾股定理，求得半径长为5.55米，再根据反正弦函数，利用计算器，算出圆弧对应圆心角的半值，然后利用比例求出圆弧长。

回答2：

玄长L=3.6米，拱高H=0.3米！求弧长C多少？
弧半径为R，弧所对的圆心角为A。
R=H/2+L^2/(8*H)
=0.3/2+3.6^2/(8*0.3)
=5.55米
A=2*ARC COS((R-H)/R)
=2*ARC COS((5.55-0.3)/5.55)
=37.849度
C=π*R*A/180=π*5.55*37.849/180=3.6663米

回答3：

解：1.8*1.8+（r-0.3）平方=r*r，r=5.55，sin0.5圆心角=1.8/5.55，圆心角=37.85，弧长=37.85/360*3.14**5.55*2=3.66米。

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