(a1+a2,a2+a3,λa1+a3) = (a1,a2,a3)K K= 1 0 λ 1 1 0 0 1 1 |K|=1+λ 由已知 r(K) = r(a1+a2,a2+a3,λa1+a3) = 3 所以 λ≠ -1.
