碳酸氢根和钙离子反应会产生沉淀吗

2025-03-14 22:17:25
推荐回答(2个)
回答1:

是不反应的。钙离子、碳酸氢根离子能在溶液里大量共存,中性溶液中能大量共存。
具体解释:

往澄清石灰水中通二氧化碳,会生成沉淀,继续通二氧化碳,沉淀溶解,便是生成了可溶于水的碳酸氢钙,这种事实就说明了钙离子与碳酸氢根离子能大量共存。
ca(oh)2
+
co2
=
caco3
+
h2o
caco3
+
co2
+
h2o
=
ca(hco3)2
或ca(oh)2
+
2co2=
ca(hco3)2

但在强酸性溶液中,hco3-会与氢离子反应,生成二氧化碳和水。

在强碱性溶液中,碳酸氢根离子会与氢氧根离子反应生成碳酸根离子,碳酸根离子继续与钙离子反应生成碳酸钙沉淀。
拓展:与钙离子和碳酸氢根离子不能大量共存的离子
与钙离子不能大量共存的离子:co3^2-,so3^2-,
与碳酸氢根离子不能大量共存的离子:h+,oh-,fe3+(双水解,下同),al3+。

回答2:

另外,补充一个知识碳酸氢钙是易溶于水的,向浑浊的氢氧化钙中继续通入二氧化碳会使其变澄清,不发生沉淀,原因就是生成了碳酸氢钙的

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