线性代数4阶行列式的计算

2024-12-07 22:07:47
推荐回答(4个)
回答1:

r2-r1*2、r3-r1、r4-r1*2

D4=|1    2    1    2|

0  -3   -1   -3

0  -1    0    0

0  -3    0   -3

提出r2公因子(-1);交换c2、c3

=|1    1    2    2|

0    1    3    3

0    0    -1   0

0    0   -3   -3

交换r3、r4;交换c3、c4

=|1   1   2   2|

0   1   3   3

0   0  -3  -3

0   0   0  -1            【这是个《上三角》】

=1*1*(-3)*(-1)

=3

拓展资料:

线性代数是数学的一个分支,它的研究对象是向量,向量空间(或称线性空间),线性变换和有限维的线性方程组。线性代数的理论是计算技术的基础,同系统工程,优化理论及稳定性理论等有着密切联系,随着计算技术的发展和计算机的普及,线性代数作为理工科的一门基础课程日益受到重视。线性代数这门课程的特点是概念比较抽象,概念之间联系很密切。内容包括行列式,矩阵,向量空间,线性方程组,矩阵的相似对角化,二次型,线性空间与线性变换等。属于大学一年级工科部分计算机及电气,经管类专业学生必修科目,也可供科技工作者阅读。线性代数的理论已被泛化为算子理论。由于科学研究中的非线性模型通常可以被近似为线性模型,使得线性代数被广泛地应用于自然科学和社会科学中。

回答2:

不一定非要出现分数,灵活处理即可。可以用下三角行列式移行,变成上三角行列式

回答3:

中午无聊,闲着没事,化化矩阵哈哈。。

回答4:

a12,a12,a11,a11,a21,a22,a23按这个顺序依次化成0
出现分数是正常的

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