如何使用汇编语言编写程序使输入的十进制数转化成十六进制的数又如何使十六进制的数转化成相应的十进制
推荐回答（2个）
CODE SEGMENT
ASSUME CS:CODE
ORG 100H
START:
PUSH CS
POP DS
PUSH CS
POP ES
CALL INPUTNUM ; 输入10进制数 转为16进制
LEA DX,LFCR
MOV AH,9
INT 21H
LEA SI,ARRAY
MOV AX,[SI]
CALL DISPAX ; 以10进制形式显示16进制数
MOV AH,4CH
INT 21H
LFCR DB 10,13,'$'
;===============================================
; 键盘输入数值数组子程序（数组名为array，元素个数存放在num中）
INPUTNUM PROC NEAR
PUSH AX
PUSH BX
PUSH CX
PUSH DX
PUSH SI
PUSH DI
PUSH BP
PUSHF
; 输入的数据以一个空格分隔，以回车符结束输入
LEA DI,ARRAY ;将数组第一个元素的有效地址置入DI
MOV WORD PTR[NUM],0
STIN:
MOV AX,0
PUSH AX
AGAIN1:
MOV AH,1
INT 21H
MOV BYTE PTR[CHAR],AL
CMP AL,13
JE LINE0
CMP AL,' '
JE LINE0
SUB AL,30H
MOV AH,0
MOV SI,AX
POP AX
MOV CL,10
MOV CH,0
MUL CX
ADD AX,SI
PUSH AX
JMP AGAIN1
LINE0:
POP AX
MOV WORD PTR[DI],AX
INC WORD PTR[NUM]
CMP BYTE PTR[CHAR],13
JE STINEND
INC DI
INC DI
JMP STIN
STINEND:
POPF
POP BP
POP DI
POP SI
POP DX
POP CX
POP BX
POP AX
RET
ARRAY DW 200 DUP(0)
NUM DW 0
CHAR DB ?
INPUTNUM ENDP
;===============================================
; 将要显示的无符号数置于 ax 中
DISPAX PROC NEAR
PUSH AX
PUSH BX
PUSH CX
PUSH DX
PUSH SI
PUSH DI
PUSH BP
PUSHF
PUSH DS
PUSH CS
POP DS
MOV BYTE PTR NZ,0
PUSH AX
LEA SI,DIVARR
MOV CX,5
@1:
POP AX
MOV DX,0
MOV BX,[SI]
DIV BX
PUSH DX
CMP AL,0
JNE @2
CMP BYTE PTR NZ,1
JE @2
CMP CX,1
JE @2
MOV DL,20H
JMP @3
@2:
ADD AL,30H
MOV DL,AL
MOV BYTE PTR NZ,1
@3:
MOV AH,2
INT 21H
INC SI
INC SI
LOOP @1
POP DX
POP DS
POPF
POP BP
POP DI
POP SI
POP DX
POP CX
POP BX
POP AX
RET
DIVARR DW 10000,1000,100,10,1
NZ DB 0
DISPAX ENDP
CODE ENDS
END START
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