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先化简,再求值:(2a+1)²-(a+2)(a-1),其中a=1/8?解:(2a+1)²-(a+2)(a-1)=4a²+4a+1-(a²+a-2)=4a²+4a+1-a²-a+2=3a²+3a+3=3(a²+a+1)将a=1/8代入得:3×[(1/8)²+1/8+1]=3×73/64=219/64