在Rt△ABC中,AC=30m,AB=50m;据勾股定理可得:BC= AB2?AC2 = 502?302 =40(m)∴小汽车的速度为v= 40 2 =20(m/s)=20×3.6(km/h)=72(km/h);∵72(km/h)>70(km/h);∴这辆小汽车超速行驶.答:这辆小汽车超速了.