(2013?徐州一模)某生物实验小组为探究酵母菌呼吸的有关问题,设计如下实验装置.实验中,先向气球中加

2025-03-26 16:37:04
推荐回答(1个)
回答1:

(1)环境因素如温度、压强的变化也可能导致实验误差,应设计一对照实验.对照实验装置与上述装置相比,将气球中的酵母菌培养液换成加热煮沸后冷却的酵母菌培养液(或不含酵母菌的培养液),观察烧杯中液面变化量.
(2)实验开始30min内,酵母菌只进行有氧呼吸,吸收的氧气与释放的二氧化碳体积相等,烧杯内液面没有发生变化.随着氧气消耗,酵母菌进行无氧呼吸产生酒精和二氧化碳,气球膨胀,液面上升.
(3)若用上述实验装置探究酵母菌无氧呼吸的适宜温度,酵母菌进行无氧呼吸,不能向气球中注入氧气;实验变量(自变量)是不同的温度,在不同的温度无氧呼吸生成的二氧化碳体积不同,因此,反应变量(因变量)通过烧杯中液面上升量表示.
(4)酵母菌进行有氧呼吸时,出芽生殖使得酵母菌数量增加,后因葡萄糖反应底物大量消耗,生成物酒精含量升高,对酵母菌有毒害作用,二氧化碳增加导致培养液PH下降,导致酵母菌种群数量下降.
故本题答案为:(1)将气球中的含酵母菌的培养液换成等量的不含酵母菌的培养液
(2)酵母菌只进行了有氧呼吸 上升 酵母菌无氧呼吸产生二氧化碳,气球膨胀
(3)①气球中不注入氧气
②取若干相同装置,并分别置于不同温度的恒温水浴锅中
(4)营养物质被大量消耗 乙醇含量过高 培养液的pH下降(任意两个均可)

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