阿Q吧 > 常温下，某一元弱酸的电离平衡常数为：Ka=10-6，对于0.01mol?L-1的该酸，下列说法不正确是（　　）A．该

常温下，某一元弱酸的电离平衡常数为：Ka=10-6，对于0.01mol?L-1的该酸，下列说法不正确是（　　）A．该

2025-03-14 21:43:34
推荐回答（1个）
回答1：

A、Ka=
[H+]?[A?]
[HA]
，有Ka?[HA]=[H+]?[A-]=10-8，c（H+）=10-4，pH=4，故A正确；
B、在弱酸溶液中加入NaOH，中和了氢离子，平衡正向移动，Ka只受温度影响，温度不变时Ka不变，故B正确；
C、等物质的量的弱酸和强碱中和后生成强碱弱酸盐，水解显碱性，在弱酸溶液中加入等体积的0.01mol?L-1NaOH溶液后，所得的溶液的pH＞7，故C错误；
D、NaA水解的离子方程式为：A-+H2O?HA-OH-，Kh=
[OH?]?[HA]
[A?]
=
KW
Ka
=
10?14
10?6
=10-8，故D正确；
故选C．

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