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阿Q吧 > 求求帮忙一物理问题，关于“阿基米德原理”

求求帮忙一物理问题，关于“阿基米德原理”

2025-04-07 20:50:20

推荐回答（3个）

回答1：

1。排水法。根据阿基米德原理，F浮=G排，将铁块全部浸入盛水的烧杯中（水不能溢出），记下浸入前后的刻度，用刻度尺测出高度差，再乘以底面积，再乘以水的密度即为排开水的重力，就等于浮力。
2。称重法。在空气中称量铁块的重力为G1，然后让其全部浸入水中，称出在水中时弹簧测力计的示数为G2，则浮力F浮=G1-G2。

回答2：

1.在量筒内加人一定量的水（足够淹没铁块）记录水的体积放入铁块再次记录水的体积用体积差根据水的密度和重力系数计算
2.烧杯加满水侧重力记录放入铁块再取出后侧重力重力差就是铁块浸没受的浮力

回答3：

2

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