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初中物理计算题，求解，要有计算步骤，谢谢！

2025-04-03 22:02:32

推荐回答（2个）

回答1：

（1）R1=U/I1=6v/0.6A=10欧；

（2）依题意，变阻器电阻不为零，故认为并联电路各支路互不干涉，I1仍为0.6A，图示电流表只能是干路电流I=1A，此时I2=I-I1=0.4A;
（3）当R2=50欧时，I2最小=U/R2=0.12A;
（4）由图可知，干路中电流表量程为I最大=3A，故变阻器最大电流为I2最大=I最大-I1=2.4A.

回答2：

话不多说、看图

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