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采用“侯氏制碱法”生产的工业纯碱(碳酸钠)中含有少量氯化钠杂质.现欲测定某工业纯碱中碳酸钠的质量分
采用“侯氏制碱法”生产的工业纯碱(碳酸钠)中含有少量氯化钠杂质.现欲测定某工业纯碱中碳酸钠的质量分
2025-03-16 03:26:54
推荐回答(1个)
回答1:
(1)设产生9g碳酸钙沉淀需要碳酸钠的质量为 x生成氯化钠的质量为y则;
Na
2
CO
3
+CaCl
2
═CaCO
3
↓+2NaCl
106 100 117
x 9g y
根据:
106
100
=
x
9g
解得:x=9.54g,根据
100
117
=
9g
y
解得y=10.53g
所以样品中Na
2
CO
3
质量分数为:
9.54g
10g
×100%=95.4%
答:纯碱样品中碳酸钠的质量分数为95.4%;
(2)原混合物中氯化钠的质量为:10g-9.54g=0.46g,所以纯碱样品中钠元素的质量为:0.46g×
23
58.5
×100%+9.54g×
46
106
×100%=4.32g,所以该工业纯碱样品中钠元素的质量分数:
4.32g
10g
×100%=43.2%.
故答案为:(1)95.4%;(2)43.2%.
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