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阿Q吧 > 10克碳酸钙与100克稀盐酸刚好完全反应,(1)产生二氧化碳多少克?(2)稀盐酸的质量分数是多少?

10克碳酸钙与100克稀盐酸刚好完全反应,(1)产生二氧化碳多少克?(2)稀盐酸的质量分数是多少?

2025-03-16 07:01:03

推荐回答（2个）

回答1：

CaCO3 + 2HCl ==== CaCl2 + CO2↑ + H2O
100/10 73/y 44/x

由 100/10 = 44/x 100/10 = 73/y
可解得 x=4.4g y=7.3g

所以生成二氧化碳4.4g 消耗盐酸的质量为7.3g

盐酸的质量分数: 7.3/100 * 100% = 7.3%

综上所述:生成二氧化碳4.4g 盐酸的质量分数为7.3%

回答2：

这么简单的化学题..带进去算就是了.列好方程式.然后列出质量分数.在把重量带进去就好了啊

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