在盐酸的电解里,加水稀释后,氢氧根的浓度为什么会增大,不是体积大了么

如上
2025-04-07 10:53:26
推荐回答(4个)
回答1:

溶液中氢氧根和氢离子是动态平衡的,水的离子积是恒定的一乘以十的负十四次方。盐酸溶液中,水电离出的氢离子可忽略不计,水的离子积kw=C[H+](盐酸电离)*C[OH-](水电离)=1*10-14。稀释后c[H+]降低,所以c[OH-]升高,是浓度问题,与体积无关。

回答2:

因为加水后,体积增大,氢离子浓度就减小,而一定温度下,离子积不变,所以氢氧根的浓度会增大。

回答3:

由于盐酸是强电解质,所以是完全电离。HCl=H+ + Cl+
当加水时,体积增大,相当于H+被稀释,所以H+浓度减少。
但根据C(H+)× C(OH-)=1×10的-14次方。(水的电离平衡常数只与温度有关)
氢离子浓度减少,而平衡常数不变,故氢氧根离子浓度增加。

回答4:

C(H+)*C(OH-)=10^14
这个是一个定值,25度时候所有的水溶液都是这样。

在盐酸的电解,H+的物质的量不变,加水稀释后,浓度减少
C(H+)降低,这个时候因为定值不变,C(OH-)自然就升高

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