三价铬离子用氢氧化钠和双氧水鉴定时的化学方程式

2025-03-16 00:15:38
推荐回答(5个)
回答1:

氯化铬溶液中先加入氢氧化钠,有沉淀生成,CrCL3+3NaOH=Cr(OH)3沉淀+3NaCL,加入过氧化

氢并水浴加热,沉淀溶解,Cr(OH)3+2NaOH+4H2O2=2NaCrO3+8H2O。

扩展资料:化学(chemistry)是自然科学的一种,主要在分子、原子层面,研究物质的组成、性

质、结构与变化规律,创造新物质(实质是自然界中原来不存在的分子)。世界由物质组成,主要

存在着化学变化和物理变化两种变化形式(还有核反应)。不同于研究尺度更小的粒子物理学与核

物理学,化学研究的原子 ~ 分子 ~ 离子(团)的物质结构和化学键、分子间作用力等相互作用,其

所在的尺度是微观世界中最接近宏观的。

回答2:

Cr3+ +3OH- ==Cr(OH)3 灰绿色沉淀
Cr(OH)3 +OH- ==CrO2- +2H2O CrO2- 亮绿色
2CrO2- +3H2O2 +2OH-===2CrO42- +4H2O 再加入过氧化氢,水浴加热使溶液变为黄色

回答3:

应该是 Cr3+ +3OH- ==Cr(OH)3 灰绿色沉淀
Cr(OH)3 +OH- ==CrO2- +2H2O CrO2- 亮绿色
2CrO2- +3H2O2 +2OH-===2CrO42- +4H2O 再加入过氧化氢,水浴加热使溶液变为黄色

回答4:

抄自百度作业帮 tnvD68rQ13

氯化铬溶液中先加入氢氧化钠 有沉淀生成
CrCL3+3NaOH=Cr(OH)3沉淀+3NaCL
加入过氧化氢并水浴加热 沉淀溶解
Cr(OH)3+2NaOH+4H2O2=2NaCrO3+8H2

回答5:

3H2O2 + 2CrO2 - + 2OH- = 2CrO4 2- + 4H2O
反应须在碱性环境下进行。

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