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高中化学,急求答案,要详细过程,题目如图,谢谢

2025-03-16 22:04:32

推荐回答（1个）

回答1：

以为HCl是强酸，NaOH是强碱，它们中和所需的物质的量是1：1，那么体积比就是浓度的反比。
1. x+y=14，这个最好就是假设法，设x=1，则y=13，那么酸和碱都是0.1mol/L，所以V酸/V碱=1
2. x+y=13，依旧设x=1，则y=12，那么酸是0.1mol/L，碱是0.01mol/L，你可以多设几个，就会发现碱始终是酸的0.1倍，即浓度比为10：1，那么酸碱体积比为1/10=0.1
3. x+y>14，y>7，x<7，所以14-y-14)表示碱的浓度，10^(-x)表示酸的浓度，酸碱体积比=碱浓度/酸浓度=10^(x+y-14)，这个值大于1，所以第二空填>
4. 酸浓度为10^(-x)，碱浓度为10^(y-14)，酸碱体积比=碱浓度/酸浓度=10^(x+y-14)=10

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