阿Q吧 > 如图所示的电路，开关S闭合时，电流表A1的示数是2.4A，电流表A2的示数是1.5A，电流表A3的示数是1.2A，则

如图所示的电路，开关S闭合时，电流表A1的示数是2.4A，电流表A2的示数是1.5A，电流表A3的示数是1.2A，则

2025-04-01 16:55:00
推荐回答（1个）
回答1：

由电路图可知，三灯泡并联，电流表A1测干路电流，电流表A2测L2和L3支路的电流之和，电流表A3测L1和L2支路的电流之和；
根据并联电路电流规律可知：
I1+I2+I3=2.4A----①
I2+I3=1.5A----②
I1+I2=1.2A----③
由①②可得，I1=0.9A；
由①③可得，I3=1.2A；
故I2=1.5A-1.2A=0.3A．
答：通过灯泡L1、L2和L3的电流分别是0.9A、0.3A、1.2A．

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