用C语言编写一个简单的计算器1

#include
int main() {
double num1 = 0; //输入1
double num2 = 0; //输入2
char ch; //操作
double ret = 0; //结果 printf( "输入第一个数:" );
scanf( "%lf", &num1 );
printf( "输入第二个数:" );
scanf( "%lf", &num2 );
printf( "操作[+ - * /]:" );
getchar();
scanf( "%c", &ch ); switch( ch ) {
case '+':
ret = num1 + num2;
break;
case '-':
ret = num1 - num2;
break;
case '*':
ret = num1 * num2;
break;
case '/':
ret = num1 / num2;
break;
default:
break;
}
printf( "结果:%.2lf\n", ret ); return 0;
} 写个简单易懂的，你操作计算器的步骤就是编写程序的思路呀

#include
int main()
{
int x,y;
char sign;
printf("输入x运算符y:");
scanf("%d %c %d",&x,&sign,&y);
if(sign=='*')
printf("%d * %d = %d\n",x,y,x*y);
else if(sign=='/')
printf("%d / %d = %d\n",x,y,x/y);
else if(sign=='%')
printf("%d Mod %d = %d\n",x,y,x%y);
else
printf("运算符输入错误！\n");
fflush(stdin);
getchar();
return 0;
}