关于java静态代码块的详细运行过程问题

2025-03-21 21:16:24
推荐回答(4个)
回答1:

废话,静态块先执行,类加载的时候就执行,一个类要想运行,首先被Java虚拟机将class文件内部字节码指令读取至内存并且包装成一个Class类型的对象,这个过程称为类加载,Class类的一个对象是对某一个类的一个描述!

不是说运行到Chinese.sing();时输出了static code,Chinese.sing();是什么?是方法调用,Chinese是类,sing是该类的静态方法,你要想调用sing方法,首先第一步就是类加载,类都没加载,Java虚拟机都不认识他,运行个屁呀!

所以第一步是类加载,注意!static块,也就是静态块,在类加载的时候就执行了,而且只执行一次,因为不可能进行第二次类加载,从这个意义上说,静态的成员是第一时间执行的,然后才轮到别人!

回答2:

static 块仅在该类被加载时执行一次

class UseStatic {   
       static int a = 3;   
       static int b;   
       static void meth(int x) {   
           System.out.println("x = " + x);  
           System.out.println("a = " + a);  
           System.out.println("b = " + b);   
     }   
      static {   
         System.out.println("Static block initialized.");
         b = a * 4;   
      }   
     public static void main(String args[]){   
          meth(42);   
   }   
}

一旦UseStatic 类被装载,所有的static语句被运行。首先,a被设置为3,接着static 块执行(打印一条消息),最后,b被初始化为a*4 或12。然后调用main(),main() 调用meth() ,把值42传递给x。3个println ( ) 语句引用两个static变量a和b,以及局部变量x 。   注意:在一个static 方法中引用任何实例变量都是非法的。 

下面是该程序的输出:  

Static block initialized.   

x = 42   

a = 3   

b = 12

回答3:

静态块在实例化类 自动调用 而不要自己写代码调用 同时他只调用一次
当没有在实例化的时候 只要你调用任何静态方法 或者是静态的属性 都会自动调用静态块、
调用的机制也是一样 只调用一次 在调用静态的任何对象之前调用

回答4:

static
{
count =2;
System.out.println("static code");
}
这是首先执行啊!没写方法名,就像在一条分叉路口,不管你选择哪条路(方法)你总要在分叉口经过吧!

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