电路分析基础问题

求解!
2024-10-22 16:28:47
推荐回答(1个)
回答1:

那么,Um = (5-2)*4/3 = 4V,红线左边等效电阻 R = Um/I = 2Ω;

因为 U=2V=Um/2,所以 R2 = R1//R3;R = 2R2//R4;

所以,加上电流源后,红线左边电路等效为:

Um=(Is1+Is2)*R//R5=8V,I = Is2 - Um/R5= -1A;