python字典的值如何打印

推测你的意图，做了一些修改：

class Chinese:
    def __int__(self):
        self._number = None
        
    def set_number(self,value): 
        if value >=1 and value <=5: 
            self._number = value 
        else: raise ValueError("Number not recognized") 
    
    def chinese(self):
        number2chinese = {1:"一",2:"二",3:"三",4:"四",5:"五"}
        return number2chinese[self._number]
        
    def set_chinese(self,value): 
        chinese2number = {"一":1,"二":2,"三":3,"四":4,"五":5} 
        if value in chinese2number: 
            self._number = chinese2number[value] 
        else: 
            raise ValueError("Chinese numeral not recognized")
        
a = Chinese()
a.set_number(3)
print(a._number)
print(a.chinese())
        
b = Chinese()
b.set_chinese("五")
print(b._number)
print(b.chinese())

运行环境Python 2.7.16, 结果：

出现你图片中问题的原因是，你在调用函数number和chinese的时候，没有给函数加上括号（），因此，你输出的就是函数的地址。加上括号了以后，才是调用函数，然后执行函数里的具体指令来输出你想要的结果。

class Chinese:
def __int__(self):
self._number = None

def number(self,value):
if value >=1 and value <=5:
self._number = value
return self._number
else:
raise ValueError("Number not recognized")

def chinese(self,value):
chinese2number = {"一":1,"二":2,"三":3,"四":4,"五":5,1:"一",2:"二",3:"三",4:"四",5:"五"}
if value in chinese2number.keys():
return chinese2number[value]
else:
raise ValueError("Chinese numeral not recognized")
a = Chinese()
print(a.number(1))
print(a.chinese(1))
print(a.chinese('一'))
b = Chinese()
print(b.number(5))
print(a.chinese(5))
print(b.chinese('五')) 

判断字典键要用dict.keys(),根据你的代码我改了一点，看能不能达到你的要求