1⼀[x^2(a^2-x^2)^1⼀2]对x的不定积分的推导过程

2024-11-02 09:17:20
推荐回答(1个)
回答1:

令x=asint,则:
sint=x/a,cost=√[1-(sint)^2]=√[1-(x/a)^2]=√(a^2-x^2)/a,dx=acostdt。
∴∫{1/[x^2√(a^2-x^2)]}dx
=∫{1/[a^2(sint)^2×acost]}acostdt
=(1/a^2)∫[1/(sint)^2]dt
=-(1/a^2)cott+C
=-(1/a^2)cost/sint+C
=-(1/a^2)[√(a^2-x^2)/a]/(x/a)+C
=-√(a^2-x^2)/(a^2x)+C
解答完毕,请指教!!!