求不定积分 ∫[x^3+1]dx⼀[x(x-1)^3]

2024-12-01 07:46:31
推荐回答(2个)
回答1:

Mathematical运行结果

回答2:

解:
(x³+1)/[x(x-1)³]=2/(x-1)³-1/x+2/(x-1)+1/(x-1)²

∫(x³+1)/[x(x-1)³] dx

=∫[2/(x-1)³-1/x+2/(x-1)+1/(x-1)²]dx

=2∫1/(x-1)³ d(x-1)-∫1/x dx+∫2/(x-1) d(x-1)+∫1/(x-1)² d(x-1)

=-1/(x-1)²-ln|x|+2ln|x-1|-1/(x-1)+C