Mathematical运行结果
解: (x³+1)/[x(x-1)³]=2/(x-1)³-1/x+2/(x-1)+1/(x-1)² ∫(x³+1)/[x(x-1)³] dx=∫[2/(x-1)³-1/x+2/(x-1)+1/(x-1)²]dx=2∫1/(x-1)³ d(x-1)-∫1/x dx+∫2/(x-1) d(x-1)+∫1/(x-1)² d(x-1)=-1/(x-1)²-ln|x|+2ln|x-1|-1/(x-1)+C