推荐回答(5个)
0011 0022 0033 0044 0055 0066 0077 0088 0099 0012 0013 0014 0015 0016 0017 0018 0019
0010 0021 0023 0024 0025 0026 0027 0028 0029 0020 0031 0032 0034 0035 0036 0037 0038
0039 0030 0041 0042 0043 0045 0046 0047 0048 0049 0040 0051 0052 0053 0054 0056 0057
0058 0059 0050 0061 0062 0063 0064 0065 0067 0068 0069 0060 0071 0072 0073 0074 0075
0076 0078 0079 0070 0081 0082 0083 0084 0085 0086 0087 0089 0080 0091 0092 0093 0094
0095 0096 0097 0098 0090 0001 0002 0003 0004 0005 0006 0007 0008 0000 0009 0098

扩展资料:
0-9四位数当然是从0到9999咯,一共10000种可能,这一万个自然数还有必要列出来么?再说百度回答只能10000个字符,肯定是写不下的.0-9两位数当然是从0到99,100个,其中1可以写成01,所以也可以看做两位数
有些密码第一位是不能为0的:
(1)如果数字不能重复,但0能放在第一位的话,10x9x8x7=5040种
(2)如果数字不能重复,且0哗害糕轿蕹计革袭宫陋不能放在第一位的话,9x9x8x7=4536种(3)如果数字能重复,但0不能放在第一位的话,9x10^3=9000种
(3)如果数字能重复,且0能放在第一位的话,10^4=10000种如果可以重复,有9000。如果不可以重复,有453610的4次方210n个。
.....0011 0022 0033 0044 0055 0066 0077 0088 0099 0012 0013 0014 0015 0016 0017 0018 0019 0010 0021 0023 0024 0025 0026 0027 0028 0029 0020 0031 0032 0034 0035 0036 0037 0038 0039 0030 0041 0042 0043 0045 0046 0047 0048 0049 0040 0051 0052 0053 0054 0056 0057 0058 0059 0050 0061 0062 0063 0064 0065 0067 0068 0069 0060 0071 0072 0073 0074 0075 0076 0078 0079 0070 0081 0082 0083 0084 0085 0086 0087 0089 0080 0091 0092 0093 0094 0095 0096 0097 0098 0090 0001 0002 0003 0004 0005 0006 0007 0008 0000 0009 0098 还有00结尾的,就是把上面的数字倒写一下就行....就不罗嗦了
int a,b,c,d;
for(a=0;a<10;a++)
for(b=0;b<10;b++)
for(c=0;c<10;c++)
for(d=0;d<10;d++)
printf("%d%d%d%d\n",a*1000+b*100+c*10+d);
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