y=cos(x^2)+sinx 求导函数

2024-11-16 15:57:06
推荐回答(4个)
回答1:

y'=(cosx²)'+(sinx)'
=-sinx²(x²)'+cosx
=-2xsinx²+cosx

回答2:

y'=(cos(x^2))'+(sinx)'
=-2x*sin(x^2) +cosx

回答3:

y'=-2xsin(x^2)+cosx

回答4:

y‘=-2xsin(x^2)+cos(x)