1⼀2!+2⼀3!+3⼀4!+......+n⼀(1+n)!求和

2024-12-04 01:48:43
推荐回答(2个)
回答1:

n/(1+n)!=1/n!-1/(n+1)!
1/2!+2/3!+3/4!+......+n/(1+n)!
=1-1/2!+1/2!-1/3!+……+1/n!-1/(n+1)!
=1-1/(n+1)!

回答2:

=1/2!+2/3!.....+(n+1-1)/(1+n)!=1/2!+2/3!...+(n-1)/n!+1/n!-1/(1+n)!=1-1/(1+n)!