当flyback 原边电感量确定后怎么根据负载判断

2025-04-01 13:52:59
推荐回答(1个)
回答1:

  反激式开关电源:初级调到112T,次级38T,辅助23T,把磁芯调到初级电感量等于1.8mH。
  反激式(Flyback)变压器,或称转换器、变换器。因其输出端在原边绕组断开电源时获得能量故而得名。

  基本原理
  当开关晶体管Tr ton时,变压器初级Np有电流 Ip,并将能量储存于其中(E = LpIp / 2).由于Np与Ns极性相反,此时二极管D反向偏压而截止,无能量传送到负载.当开关Tr off 时,由楞次定律: (e = -N△Φ/△T)可知,变压器原边绕组将产生一反向电势,此时二极管D正向导通,负载有电流IL流通.反激式转换器之稳态波形
  导通时间 ton的大小将决定Ip、Vce的幅值:
  Vce max = VIN / 1-Dmax
  VIN: 输入直流电压 ; Dmax : 最大工作周期
  Dmax = ton / T
  由此可知,想要得到低的集电极电压,必须保持低的Dmax,也就是Dmax<0.5,在实际应用中通常取Dmax = 0.4,以限制Vcemax ≦ 2.2VIN.
  开关管Tr on时的集电极工作电流Ie,也就是原边峰值电流Ip为: Ic = Ip = IL / n. 因IL = Io,故当Io一定时,匝比 n的大小即决定了Ic的大小,上式是按功率守恒原则,原副边安匝数 相等 NpIp = NsIs而导出. Ip亦可用下列方法表示:
  Ic = Ip = 2Po / (η*VIN*Dmax)η: 转换器的效率
  公式导出如下:
  输出功率 : Po = LIp2η / 2T
  输入电压 : VIN = Ldi / dt设 di = Ip,且 1 / dt = f / Dmax,则:
  VIN = LIpf / Dmax 或 Lp = VIN*Dmax / Ipf
  则Po又可表示为 :
  Po = ηVINf DmaxIp2 / 2f Ip = 1/2ηVINDmaxIp
  ∴Ip = 2Po / ηVINDmax
  上列公式中 :
  VIN : 最小直流输入电压 (V)
  Dmax : 最大导通占空比
  Lp : 变压器初级电感 (mH)
  Ip : 变压器原边峰值电流 (A)
  f : 转换频率 (KHZ)
  

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