已知(x+y)^2=25,(x-y)^2=9,求xy与x^2+y^2的值

2024-11-20 07:31:05
推荐回答(4个)
回答1:

已知(x+y)^2=25,(x-y)^2=9,
xy=((x+y)^2-(x-y)^2)/4=4;
x²+y²=25-2*4=17

回答2:

(x+y)²=25 (x-y)²=9即,
x²+y²+2xy=25 x²+y²-2xy=9
两式相加得
2﹙x²+y²﹚=25+9=34
x²+y²=17

回答3:

因为:(x+y)^2=x^2+2xy+y^2
(x-y)^2=x^2-2xy+y^2
所以:(x+y)^2+(x-y)^2
=2x^2+2y^2
=2(x^2+y^2)
=25+9=36
则:x^2+y^2=36/2=18
(x+y)^2-x^2+y^2=2xy=25-18=7
xy=7/2=3.5

回答4:

17