(1)两电阻串联时,R=R1+R2=20Ω+60Ω=80Ω,串联电路电流处处相等,则I1:I2=1:1;(2)两电阻并联, 1 R并 = 1 R1 + 1 R2 ,R并= R1R2 R1+R2 = 20Ω×60Ω 20Ω+60Ω =15Ω,并联电路电压相等,通过电阻电流之比: I1 I2 = U R1 U R2 = R2 R1 = 60Ω 20Ω = 3 1 ;故答案为:80;1:1;15;3:1.