1/(X-4)+4/(X-1)=2/(X-3)+3/(x-2)
1/(x-4)-2/(x-3)=3/(x-2)-4/(x-1)
[(x-3)-2(x-4)]/(x-4)(x-3)=[3(x-1)-4(x-2)]/(x-2)(x-1)
(5-x)/(x^2-7x+12)=(5-x)/(x^2-3x+2)
(1):5-x=0
x=5
(2):x^2-7x+12=x^2-3x+2
x=2.5
即方程的解是：X1=5，X2=2。5
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