1. 第一种情况下循环队列中共有25个元素:(rear - front + max)%max = (48 - 23 + 60) % 60 = 25第二种情况下共有35个元素:(rear - front + max)%max = (23 - 48 + 60) % 60 = 352.判断空:rear == front3.判断满:(rear+1)%max == front